{"id":1774,"date":"2025-05-09T11:45:06","date_gmt":"2025-05-09T11:45:06","guid":{"rendered":"https:\/\/yaveni.com\/blog\/?p=1774"},"modified":"2025-05-09T11:45:07","modified_gmt":"2025-05-09T11:45:07","slug":"the-electron-domain-and-molecular-geometry-of-so3-are","status":"publish","type":"post","link":"https:\/\/gaviki.com\/blog\/the-electron-domain-and-molecular-geometry-of-so3-are\/","title":{"rendered":"The electron domain and molecular geometry of SO3 are"},"content":{"rendered":"\n<p>The electron domain and molecular geometry of SO3 are <\/p>\n\n\n\n<p>A) trigonal planar, bent <\/p>\n\n\n\n<p>B) trigonal bipyramidal, trigonal planar <\/p>\n\n\n\n<p>C) octahedral, seesaw <\/p>\n\n\n\n<p>D) trigonal bipyramidal, T-shaped El trigonal planar, trigonal planar<\/p>\n\n\n\n<p><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-vivid-cyan-blue-color\"><strong>The correct answer and explanation is :<\/strong><\/mark><\/p>\n\n\n\n<p>The correct answer is:<br><strong>E) trigonal planar, trigonal planar<\/strong><\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Explanation:<\/h3>\n\n\n\n<p><strong>1. Determining the Electron Domain Geometry:<\/strong><\/p>\n\n\n\n<p>To determine the <strong>electron domain geometry<\/strong> of SO\u2083 (sulfur trioxide), we start by analyzing its <strong>Lewis structure<\/strong>:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>Sulfur (S)<\/strong> is the central atom. It has 6 valence electrons.<\/li>\n\n\n\n<li>Each <strong>oxygen (O)<\/strong> atom also has 6 valence electrons, and there are <strong>three<\/strong> of them.<\/li>\n\n\n\n<li>Total valence electrons = 6 (from S) + 3 \u00d7 6 (from O) = 24 electrons.<\/li>\n<\/ul>\n\n\n\n<p>When drawing the Lewis structure, sulfur forms <strong>double bonds<\/strong> with each of the three oxygen atoms. This satisfies the octet rule for each oxygen, and sulfur uses <strong>12 electrons<\/strong> (or six bonding pairs), which is acceptable because sulfur can <strong>expand its octet<\/strong> as it is in Period 3 of the periodic table.<\/p>\n\n\n\n<p>Thus, there are <strong>three regions of electron density<\/strong> (double bonds count as one region each) around the sulfur atom. These three bonding regions will <strong>repel<\/strong> each other and arrange themselves as far apart as possible, resulting in a <strong>trigonal planar electron domain geometry<\/strong>.<\/p>\n\n\n\n<p><strong>2. Determining the Molecular Geometry:<\/strong><\/p>\n\n\n\n<p>In SO\u2083, <strong>all three electron domains are bonding pairs<\/strong>, and there are <strong>no lone pairs<\/strong> on the central sulfur atom. When there are no lone pairs, the <strong>molecular geometry<\/strong> is the same as the <strong>electron domain geometry<\/strong>.<\/p>\n\n\n\n<p>Therefore, the molecular geometry of SO\u2083 is also <strong>trigonal planar<\/strong>.<\/p>\n\n\n\n<p><strong>3. Bond Angles:<\/strong><\/p>\n\n\n\n<p>In a trigonal planar geometry, the ideal bond angles are <strong>120\u00b0<\/strong>, and in SO\u2083, the molecule is symmetrical, so all S\u2013O bonds are equivalent and the angles are approximately 120\u00b0.<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Summary:<\/h3>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>Electron Domain Geometry:<\/strong> Trigonal Planar<\/li>\n\n\n\n<li><strong>Molecular Geometry:<\/strong> Trigonal Planar<\/li>\n\n\n\n<li><strong>Correct Answer:<\/strong> <strong>E<\/strong><\/li>\n<\/ul>\n","protected":false},"excerpt":{"rendered":"<p>The electron domain and molecular geometry of SO3 are A) trigonal planar, bent B) trigonal bipyramidal, trigonal planar C) octahedral, seesaw D) trigonal bipyramidal, T-shaped El trigonal planar, trigonal planar The correct answer and explanation is : The correct answer is:E) trigonal planar, trigonal planar Explanation: 1. Determining the Electron Domain Geometry: To determine the [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[],"tags":[],"class_list":["post-1774","post","type-post","status-publish","format-standard","hentry"],"_links":{"self":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/1774","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/comments?post=1774"}],"version-history":[{"count":1,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/1774\/revisions"}],"predecessor-version":[{"id":1775,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/1774\/revisions\/1775"}],"wp:attachment":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/media?parent=1774"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/categories?post=1774"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/tags?post=1774"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}