{"id":17577,"date":"2025-06-12T13:32:34","date_gmt":"2025-06-12T13:32:34","guid":{"rendered":"https:\/\/gaviki.com\/blog\/?p=17577"},"modified":"2025-06-12T13:32:37","modified_gmt":"2025-06-12T13:32:37","slug":"what-would-the-lewis-dot-structure-look-like-for-bri2","status":"publish","type":"post","link":"https:\/\/gaviki.com\/blog\/what-would-the-lewis-dot-structure-look-like-for-bri2\/","title":{"rendered":"What would the Lewis dot structure look like for BrI2-"},"content":{"rendered":"\n<p>What would the Lewis dot structure look like for BrI2-? What is its electron geometry? What is its molecular geometry? Is it polar or nonpolar?<\/p>\n\n\n\n<p><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-vivid-cyan-blue-color\"><strong>The correct answer and explanation is:<\/strong><\/mark><\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Lewis Dot Structure for <strong>BrI\u2082\u207b<\/strong>:<\/h3>\n\n\n\n<p>To draw the Lewis structure for BrI\u2082\u207b, follow these steps:<\/p>\n\n\n\n<ol class=\"wp-block-list\">\n<li><strong>Count valence electrons:<\/strong>\n<ul class=\"wp-block-list\">\n<li>Br (group 17): 7 valence electrons<\/li>\n\n\n\n<li>Each I (group 17): 7 valence electrons \u00d7 2 = 14<\/li>\n\n\n\n<li>Plus 1 extra electron for the negative charge: +1<br><strong>Total = 7 + 14 + 1 = 22 valence electrons<\/strong><\/li>\n<\/ul>\n<\/li>\n\n\n\n<li><strong>Determine the central atom:<\/strong><br>Bromine (Br) is less electronegative than iodine (I), so Br is the central atom.<\/li>\n\n\n\n<li><strong>Form single bonds between Br and each I:<\/strong><br>Use 2 electrons per bond \u2192 2 bonds = 4 electrons used.<br><strong>Remaining = 22 &#8211; 4 = 18 electrons<\/strong><\/li>\n\n\n\n<li><strong>Distribute remaining electrons to satisfy octets for outer atoms (I):<\/strong><br>Each I needs 6 more electrons (to complete 8).<br>6 \u00d7 2 = 12 electrons used.<br><strong>Remaining = 18 &#8211; 12 = 6 electrons<\/strong><\/li>\n\n\n\n<li><strong>Place remaining electrons on Br (central atom):<\/strong><br>Br gets the last 6 electrons as lone pairs.<\/li>\n\n\n\n<li><strong>Check for expanded octet:<\/strong><br>Br has 2 bond pairs and 3 lone pairs = 10 electrons.<br>This is acceptable because Br can expand its octet (period 4 element).<\/li>\n<\/ol>\n\n\n\n<p><strong>Lewis Structure:<\/strong><\/p>\n\n\n\n<pre class=\"wp-block-code\"><code>     I\n     |\nI \u2014 Br\u207b \u2014 I\n     :\n   .. ..\n<\/code><\/pre>\n\n\n\n<p>(Three lone pairs on Br, three lone pairs on each I.)<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>Electron Geometry:<\/strong><\/h3>\n\n\n\n<ul class=\"wp-block-list\">\n<li>With 5 regions of electron density (2 bonding pairs + 3 lone pairs), the **electron geometry is <strong>trigonal bipyramidal<\/strong>.<\/li>\n<\/ul>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>Molecular Geometry:<\/strong><\/h3>\n\n\n\n<ul class=\"wp-block-list\">\n<li>The 3 lone pairs occupy equatorial positions.<\/li>\n\n\n\n<li>The two I atoms occupy axial positions.<\/li>\n\n\n\n<li><strong>Molecular geometry: Linear<\/strong><\/li>\n<\/ul>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>Polarity:<\/strong><\/h3>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Although the molecule has polar bonds, the <strong>molecular geometry is linear<\/strong> and <strong>symmetrical<\/strong>, so dipoles cancel.<\/li>\n\n\n\n<li><strong>BrI\u2082\u207b is nonpolar.<\/strong><\/li>\n<\/ul>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\">Summary:<\/h3>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>Lewis Structure:<\/strong> Br central with two I atoms and 3 lone pairs<\/li>\n\n\n\n<li><strong>Electron Geometry:<\/strong> Trigonal bipyramidal<\/li>\n\n\n\n<li><strong>Molecular Geometry:<\/strong> Linear<\/li>\n\n\n\n<li><strong>Polarity:<\/strong> Nonpolar<\/li>\n<\/ul>\n","protected":false},"excerpt":{"rendered":"<p>What would the Lewis dot structure look like for BrI2-? What is its electron geometry? What is its molecular geometry? Is it polar or nonpolar? The correct answer and explanation is: Lewis Dot Structure for BrI\u2082\u207b: To draw the Lewis structure for BrI\u2082\u207b, follow these steps: Lewis Structure: (Three lone pairs on Br, three lone [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1],"tags":[],"class_list":["post-17577","post","type-post","status-publish","format-standard","hentry","category-quiz-questions"],"_links":{"self":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/17577","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/comments?post=17577"}],"version-history":[{"count":1,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/17577\/revisions"}],"predecessor-version":[{"id":17580,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/17577\/revisions\/17580"}],"wp:attachment":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/media?parent=17577"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/categories?post=17577"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/tags?post=17577"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}