{"id":17407,"date":"2025-06-12T12:03:57","date_gmt":"2025-06-12T12:03:57","guid":{"rendered":"https:\/\/gaviki.com\/blog\/?p=17407"},"modified":"2025-06-12T12:04:04","modified_gmt":"2025-06-12T12:04:04","slug":"how-many-lone-pairs-of-electrons-are-on-the-i-atom-in-if4","status":"publish","type":"post","link":"https:\/\/gaviki.com\/blog\/how-many-lone-pairs-of-electrons-are-on-the-i-atom-in-if4\/","title":{"rendered":"How many lone pairs of electrons are on the I atom in IF4+"},"content":{"rendered":"\n<p>How many lone pairs of electrons are on the I atom in IF4+? Question 23 options: 0 1 2 3<\/p>\n\n\n\n<p><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-vivid-cyan-blue-color\"><strong>The correct answer and explanation is:<\/strong><\/mark><\/p>\n\n\n\n<p>The correct answer is: <strong>1 lone pair<\/strong><\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\">Explanation (Approximately 300 words):<\/h3>\n\n\n\n<p>To determine the number of lone pairs of electrons on the iodine (I) atom in <strong>IF\u2084\u207a<\/strong>, we need to use principles from <strong>valence shell electron pair repulsion (VSEPR) theory<\/strong> and electron counting.<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\">Step 1: Determine the number of valence electrons<\/h3>\n\n\n\n<p>Iodine (I) is in group 17 of the periodic table and has <strong>7 valence electrons<\/strong>. Each fluorine (F) atom forms a single bond with iodine, and there are 4 fluorine atoms, contributing 4 bonding pairs (or 8 electrons).<\/p>\n\n\n\n<p>However, because the species is a <strong>positively charged ion (IF\u2084\u207a)<\/strong>, <strong>one electron is removed<\/strong>, reducing the total electron count by 1.<\/p>\n\n\n\n<p>So the total electron count on iodine becomes:<\/p>\n\n\n\n<p><strong>7 (from I) \u2212 1 (positive charge) = 6 valence electrons available for bonding\/lone pairs<\/strong><\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\">Step 2: Count the bonding pairs<\/h3>\n\n\n\n<p>Each F atom forms a single bond with I, accounting for <strong>4 bonding pairs<\/strong>, which equals <strong>8 bonding electrons<\/strong>. These electrons are shared between iodine and fluorine, and they count toward the <strong>electron domain<\/strong> around iodine.<\/p>\n\n\n\n<p>Now, subtract the 4 bonding pairs (8 electrons) from the available 6 valence electrons on iodine:<\/p>\n\n\n\n<p>But wait\u2014this isn\u2019t quite right. Let\u2019s reframe this using <strong>electron domains<\/strong>, which VSEPR theory uses.<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\">Step 3: Apply VSEPR theory<\/h3>\n\n\n\n<p>Iodine has:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>4 bonded fluorine atoms = <strong>4 bonding pairs<\/strong><\/li>\n\n\n\n<li>Total valence electron pairs around iodine = <strong>5 electron domains<\/strong> (since 6 valence electrons gives 3 pairs; but 4 are used in bonding, and 1 remains as a lone pair)<\/li>\n<\/ul>\n\n\n\n<p>So, iodine in IF\u2084\u207a has:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>4 bonding pairs<\/strong> (shared with fluorine)<\/li>\n\n\n\n<li><strong>1 lone pair<\/strong> of electrons<\/li>\n<\/ul>\n\n\n\n<p>This makes the molecular geometry <strong>seesaw<\/strong> (5 electron domains: 4 bonds + 1 lone pair), derived from a <strong>trigonal bipyramidal<\/strong> electron geometry.<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\">Final Answer: <strong>1 lone pair<\/strong> on the iodine atom in IF\u2084\u207a.<\/h3>\n","protected":false},"excerpt":{"rendered":"<p>How many lone pairs of electrons are on the I atom in IF4+? Question 23 options: 0 1 2 3 The correct answer and explanation is: The correct answer is: 1 lone pair Explanation (Approximately 300 words): To determine the number of lone pairs of electrons on the iodine (I) atom in IF\u2084\u207a, we need [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1],"tags":[],"class_list":["post-17407","post","type-post","status-publish","format-standard","hentry","category-quiz-questions"],"_links":{"self":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/17407","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/comments?post=17407"}],"version-history":[{"count":1,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/17407\/revisions"}],"predecessor-version":[{"id":17408,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/17407\/revisions\/17408"}],"wp:attachment":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/media?parent=17407"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/categories?post=17407"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/tags?post=17407"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}