If 3x – 13 = 8, the value of x \u2013 1 is<\/p>\n\n\n\n
The correct answer and explanation is:<\/strong><\/mark><\/p>\n\n\n\n We are given the equation: 3x\u221213=83x – 13 = 8<\/p>\n\n\n\n To isolate xx, we first get rid of the constant on the left-hand side: 3x\u221213+13=8+133x=213x – 13 + 13 = 8 + 13 \\\\ 3x = 21<\/p>\n\n\n\n Now divide both sides by 3: x=213=7x = \\frac{21}{3} = 7<\/p>\n\n\n\n Now that we know x=7x = 7, substitute that into x\u22121x – 1: x\u22121=7\u22121=6x – 1 = 7 – 1 = \\boxed{6}<\/p>\n\n\n\n This problem is a basic linear equation, which is a fundamental concept in algebra. The equation given is 3x\u221213=83x – 13 = 8. The goal is to isolate the variable xx on one side of the equation in order to find its value. This process involves two main steps: removing constants and then removing coefficients.<\/p>\n\n\n\n First, we add 13 to both sides of the equation to eliminate the “-13” on the left-hand side. Adding the same value to both sides of an equation is allowed because it maintains equality \u2014 it\u2019s like balancing a scale. When we do this, we get: 3x=213x = 21<\/p>\n\n\n\n Next, we want to solve for xx, but it\u2019s currently multiplied by 3. To undo this multiplication, we divide both sides by 3: x=7x = 7<\/p>\n\n\n\n This gives us the value of xx. But the question doesn\u2019t ask directly for xx; it asks for x\u22121x – 1. This is a simple substitution step. Since x=7x = 7, we compute 7\u221217 – 1, which equals 6.<\/p>\n\n\n\n This problem illustrates how solving equations can be methodical and logical. Each operation you perform has a clear purpose, and it brings you closer to isolating the variable. These steps \u2014 adding, subtracting, multiplying, and dividing \u2014 are the basic tools used throughout algebra to solve equations. Understanding them builds a strong foundation for more advanced math.<\/p>\n\n\n\n 6\\boxed{6}<\/p>\n","protected":false},"excerpt":{"rendered":" If 3x – 13 = 8, the value of x \u2013 1 is The correct answer and explanation is: We are given the equation: 3x\u221213=83x – 13 = 8 Step 1: Solve for xx To isolate xx, we first get rid of the constant on the left-hand side: 3x\u221213+13=8+133x=213x – 13 + 13 = 8 […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1],"tags":[],"class_list":["post-17370","post","type-post","status-publish","format-standard","hentry","category-quiz-questions"],"_links":{"self":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/17370","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/comments?post=17370"}],"version-history":[{"count":1,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/17370\/revisions"}],"predecessor-version":[{"id":17371,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/17370\/revisions\/17371"}],"wp:attachment":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/media?parent=17370"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/categories?post=17370"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/tags?post=17370"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}Step 1: Solve for xx<\/h3>\n\n\n\n
Step 2: Find the value of x\u22121x – 1<\/h3>\n\n\n\n
\n\n\n\n300-Word Explanation:<\/h3>\n\n\n\n
Final Answer:<\/h3>\n\n\n\n