{"id":16943,"date":"2025-06-12T06:24:25","date_gmt":"2025-06-12T06:24:25","guid":{"rendered":"https:\/\/gaviki.com\/blog\/?p=16943"},"modified":"2025-06-12T06:24:47","modified_gmt":"2025-06-12T06:24:47","slug":"the-lewis-structure-for-c2h2-contains","status":"publish","type":"post","link":"https:\/\/gaviki.com\/blog\/the-lewis-structure-for-c2h2-contains\/","title":{"rendered":"The Lewis structure for C2H2 contains"},"content":{"rendered":"\n<p class=\"wp-block-paragraph\">The Lewis structure for C2H2 contains: a) how many single bonds, b) how many double bonds, c) how many triple bonds and d) how many lone pairs?<\/p>\n\n\n\n<p class=\"wp-block-paragraph\"><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-vivid-cyan-blue-color\"><strong>The correct answer and explanation is:<\/strong><\/mark><\/p>\n\n\n\n<p class=\"wp-block-paragraph\"><strong>Correct Answers:<\/strong><br>a) <strong>2 single bonds<\/strong><br>b) <strong>0 double bonds<\/strong><br>c) <strong>1 triple bond<\/strong><br>d) <strong>2 lone pairs<\/strong><\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\">Explanation (Approx. 300 words):<\/h3>\n\n\n\n<p class=\"wp-block-paragraph\">C\u2082H\u2082 is the molecular formula for <strong>ethyne<\/strong>, also known as <strong>acetylene<\/strong>. To determine the bonding and lone pairs in its Lewis structure, we follow a systematic approach.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\"><strong>Step 1: Count the valence electrons.<\/strong><\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Carbon (C) has 4 valence electrons, and there are two carbon atoms: 4 \u00d7 2 = 8<\/li>\n\n\n\n<li>Hydrogen (H) has 1 valence electron, and there are two hydrogen atoms: 1 \u00d7 2 = 2<\/li>\n\n\n\n<li>Total = 8 + 2 = <strong>10 valence electrons<\/strong><\/li>\n<\/ul>\n\n\n\n<p class=\"wp-block-paragraph\"><strong>Step 2: Determine the bonding arrangement.<\/strong><br>Ethyne is a linear molecule. The skeletal structure places the carbon atoms bonded to each other, with each carbon also bonded to one hydrogen:<\/p>\n\n\n\n<p class=\"wp-block-paragraph\"><strong>H\u2013C\u2261C\u2013H<\/strong><\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Between the two carbon atoms, a <strong>triple bond<\/strong> forms, using 6 electrons (3 shared pairs). Each hydrogen is connected to a carbon by a <strong>single bond<\/strong>, using 2 more electrons (1 pair per H\u2013C bond). So far, 8 electrons are used (6 in the triple bond and 1 each in the two C\u2013H single bonds). That leaves <strong>2 electrons<\/strong>, or <strong>1 lone pair<\/strong>.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Each carbon atom follows the octet rule. In the structure:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Carbon atoms share 6 electrons with each other and 2 electrons with hydrogen, totaling 8.<\/li>\n\n\n\n<li>Hydrogen atoms follow the duet rule (only need 2 electrons), satisfied by the single C\u2013H bonds.<\/li>\n<\/ul>\n\n\n\n<p class=\"wp-block-paragraph\"><strong>Step 3: Assign lone pairs.<\/strong><br>Hydrogen never has lone pairs. The remaining 2 electrons are assigned as lone pairs. In the Lewis structure, <strong>each carbon atom has one lone pair<\/strong>, totaling <strong>2 lone pairs<\/strong>.<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Summary:<\/h3>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>Single bonds:<\/strong> 2 (each C\u2013H)<\/li>\n\n\n\n<li><strong>Double bonds:<\/strong> 0<\/li>\n\n\n\n<li><strong>Triple bonds:<\/strong> 1 (between the carbon atoms)<\/li>\n\n\n\n<li><strong>Lone pairs:<\/strong> 2 (1 on each carbon)<\/li>\n<\/ul>\n\n\n\n<p class=\"wp-block-paragraph\">This structure satisfies the octet rule for carbon and duet rule for hydrogen.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>The Lewis structure for C2H2 contains: a) how many single bonds, b) how many double bonds, c) how many triple bonds and d) how many lone pairs? The correct answer and explanation is: Correct Answers:a) 2 single bondsb) 0 double bondsc) 1 triple bondd) 2 lone pairs Explanation (Approx. 300 words): C\u2082H\u2082 is the molecular [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1],"tags":[],"class_list":["post-16943","post","type-post","status-publish","format-standard","hentry","category-quiz-questions"],"_links":{"self":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/16943","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/comments?post=16943"}],"version-history":[{"count":1,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/16943\/revisions"}],"predecessor-version":[{"id":16944,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/16943\/revisions\/16944"}],"wp:attachment":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/media?parent=16943"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/categories?post=16943"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/tags?post=16943"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}