{"id":16468,"date":"2025-06-11T13:42:42","date_gmt":"2025-06-11T13:42:42","guid":{"rendered":"https:\/\/gaviki.com\/blog\/?p=16468"},"modified":"2025-06-11T13:42:45","modified_gmt":"2025-06-11T13:42:45","slug":"the-sigma-bond-between-the-carbon-and-oxygen-in-co2-is-formed-from-which-two-orbitals","status":"publish","type":"post","link":"https:\/\/gaviki.com\/blog\/the-sigma-bond-between-the-carbon-and-oxygen-in-co2-is-formed-from-which-two-orbitals\/","title":{"rendered":"The sigma bond between the carbon and oxygen in CO2 is formed from which two orbitals"},"content":{"rendered":"\n<p>The sigma bond between the carbon and oxygen in CO2 is formed from which two orbitals<\/p>\n\n\n\n<p><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-vivid-cyan-blue-color\"><strong>The correct answer and explanation is:<\/strong><\/mark><\/p>\n\n\n\n<p><strong>Correct Answer:<\/strong><br>The sigma (\u03c3) bond between the carbon and oxygen atoms in carbon dioxide (CO\u2082) is formed from the <strong>sp hybrid orbital of carbon<\/strong> and the <strong>sp\u00b2 hybrid orbital of oxygen<\/strong>.<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>Explanation (Approx. 300 words):<\/strong><\/h3>\n\n\n\n<p>Carbon dioxide (CO\u2082) is a linear molecule with the structure O=C=O. It consists of one carbon atom double bonded to each of two oxygen atoms. Each of these double bonds is composed of one <strong>sigma (\u03c3) bond<\/strong> and one <strong>pi (\u03c0) bond<\/strong>.<\/p>\n\n\n\n<h4 class=\"wp-block-heading\"><strong>Hybridization of Carbon in CO\u2082:<\/strong><\/h4>\n\n\n\n<p>Carbon has the ground-state electron configuration of 1s\u00b2 2s\u00b2 2p\u00b2. To form bonds, carbon undergoes <strong>sp hybridization<\/strong> in CO\u2082. In this hybridization, one 2s orbital and one 2p orbital mix to form two sp hybrid orbitals that align linearly at 180\u00b0 angles. These sp orbitals form the sigma bonds with oxygen atoms, and the unhybridized p orbitals are used for the pi bonds.<\/p>\n\n\n\n<h4 class=\"wp-block-heading\"><strong>Hybridization of Oxygen in CO\u2082:<\/strong><\/h4>\n\n\n\n<p>Oxygen, with a ground-state configuration of 1s\u00b2 2s\u00b2 2p\u2074, typically undergoes <strong>sp\u00b2 hybridization<\/strong> in CO\u2082. Each oxygen atom uses one of its sp\u00b2 hybrid orbitals to form a sigma bond with carbon. The remaining sp\u00b2 orbitals hold lone pairs, while the unhybridized p orbital participates in the pi bond.<\/p>\n\n\n\n<h4 class=\"wp-block-heading\"><strong>Sigma Bond Formation:<\/strong><\/h4>\n\n\n\n<p>The sigma bond is the first bond formed between two atoms and involves <strong>end-to-end (axial) overlap<\/strong> of orbitals. In CO\u2082:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>The carbon atom uses an <strong>sp hybrid orbital<\/strong>.<\/li>\n\n\n\n<li>The oxygen atom uses an <strong>sp\u00b2 hybrid orbital<\/strong>.<br>These orbitals overlap head-on to form a strong sigma bond along the internuclear axis.<\/li>\n<\/ul>\n\n\n\n<h4 class=\"wp-block-heading\"><strong>Pi Bond Formation:<\/strong><\/h4>\n\n\n\n<p>The remaining unhybridized p orbitals on carbon and oxygen overlap sideways to form pi bonds, completing the double bonds.<\/p>\n\n\n\n<p>In conclusion, the <strong>sigma bond in each C=O bond in CO\u2082<\/strong> arises from the <strong>overlap of a carbon sp hybrid orbital with an oxygen sp\u00b2 hybrid orbital<\/strong>.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>The sigma bond between the carbon and oxygen in CO2 is formed from which two orbitals The correct answer and explanation is: Correct Answer:The sigma (\u03c3) bond between the carbon and oxygen atoms in carbon dioxide (CO\u2082) is formed from the sp hybrid orbital of carbon and the sp\u00b2 hybrid orbital of oxygen. Explanation (Approx. [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1],"tags":[],"class_list":["post-16468","post","type-post","status-publish","format-standard","hentry","category-quiz-questions"],"_links":{"self":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/16468","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/comments?post=16468"}],"version-history":[{"count":1,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/16468\/revisions"}],"predecessor-version":[{"id":16469,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/16468\/revisions\/16469"}],"wp:attachment":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/media?parent=16468"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/categories?post=16468"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/tags?post=16468"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}