{"id":16352,"date":"2025-06-11T09:05:50","date_gmt":"2025-06-11T09:05:50","guid":{"rendered":"https:\/\/gaviki.com\/blog\/?p=16352"},"modified":"2025-06-11T09:05:53","modified_gmt":"2025-06-11T09:05:53","slug":"martin-puts-two-bowls-of-fruit-out-for-his-friends","status":"publish","type":"post","link":"https:\/\/gaviki.com\/blog\/martin-puts-two-bowls-of-fruit-out-for-his-friends\/","title":{"rendered":"Martin puts two bowls of fruit out for his friends"},"content":{"rendered":"\n<p>Martin puts two bowls of fruit out for his friends. The bowl of grapes has 9 green grapes and 16 red grapes. The bowl of tangerines has 7 seeded and 3 seedless tangerines. Martin&#8217;s friend chooses a random grape and a random tangerine. What is the probability that she chooses a green grape and a seedless tangerine?<\/p>\n\n\n\n<p><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-vivid-cyan-blue-color\"><strong>The correct answer and explanation is:<\/strong><\/mark><\/p>\n\n\n\n<p>To find the probability that Martin&#8217;s friend chooses a <strong>green grape<\/strong> and a <strong>seedless tangerine<\/strong>, we can use the <strong>multiplication rule for independent events<\/strong>, since choosing a grape and choosing a tangerine are separate, independent events.<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\">Step 1: Total number of grapes<\/h3>\n\n\n\n<p>There are:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>9 green grapes<\/li>\n\n\n\n<li>16 red grapes<br><strong>Total grapes = 9 + 16 = 25<\/strong><\/li>\n<\/ul>\n\n\n\n<p>So, the probability of choosing a <strong>green grape<\/strong> is: P(green&nbsp;grape)=925P(\\text{green grape}) = \\frac{9}{25}<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\">Step 2: Total number of tangerines<\/h3>\n\n\n\n<p>There are:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>7 seeded tangerines<\/li>\n\n\n\n<li>3 seedless tangerines<br><strong>Total tangerines = 7 + 3 = 10<\/strong><\/li>\n<\/ul>\n\n\n\n<p>So, the probability of choosing a <strong>seedless tangerine<\/strong> is: P(seedless&nbsp;tangerine)=310P(\\text{seedless tangerine}) = \\frac{3}{10}<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\">Step 3: Multiply the two probabilities<\/h3>\n\n\n\n<p>Since both selections are independent, multiply the probabilities: P(green&nbsp;grape&nbsp;and&nbsp;seedless&nbsp;tangerine)=925\u00d7310=27250P(\\text{green grape and seedless tangerine}) = \\frac{9}{25} \\times \\frac{3}{10} = \\frac{27}{250}<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\">\u2705 Final Answer: <strong>27250\\frac{27}{250}<\/strong><\/h3>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\">\ud83d\udcd8 Explanation (Approx. 300 words)<\/h3>\n\n\n\n<p>To solve this probability problem, it\u2019s important to recognize that two separate events are occurring: one fruit is selected from the bowl of grapes, and one from the bowl of tangerines. Since these actions don\u2019t affect each other (the selection of a grape doesn&#8217;t impact the selection of a tangerine), we treat them as <strong>independent events<\/strong>. This means we can find the overall probability by <strong>multiplying<\/strong> the probabilities of each individual event.<\/p>\n\n\n\n<p>First, we calculate the probability of selecting a green grape. The grape bowl contains 9 green grapes out of a total of 25 (9 green + 16 red). Therefore, the chance of picking a green grape is 9 out of 25, or 925\\frac{9}{25}.<\/p>\n\n\n\n<p>Next, we find the probability of selecting a seedless tangerine. There are 3 seedless tangerines in a total of 10 (7 seeded + 3 seedless), so the probability of picking a seedless tangerine is 310\\frac{3}{10}.<\/p>\n\n\n\n<p>To find the probability of <strong>both<\/strong> events happening together\u2014selecting a green grape <strong>and<\/strong> a seedless tangerine\u2014we multiply the two individual probabilities: 925\u00d7310=27250\\frac{9}{25} \\times \\frac{3}{10} = \\frac{27}{250}<\/p>\n\n\n\n<p>This product represents the likelihood that both specific types of fruit are chosen at random. Fraction multiplication is straightforward: multiply the numerators (top numbers) together and multiply the denominators (bottom numbers) together. This gives us the final answer: 27250\\frac{27}{250}, which cannot be simplified further.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>Martin puts two bowls of fruit out for his friends. The bowl of grapes has 9 green grapes and 16 red grapes. The bowl of tangerines has 7 seeded and 3 seedless tangerines. Martin&#8217;s friend chooses a random grape and a random tangerine. What is the probability that she chooses a green grape and a [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1],"tags":[],"class_list":["post-16352","post","type-post","status-publish","format-standard","hentry","category-quiz-questions"],"_links":{"self":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/16352","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/comments?post=16352"}],"version-history":[{"count":1,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/16352\/revisions"}],"predecessor-version":[{"id":16353,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/16352\/revisions\/16353"}],"wp:attachment":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/media?parent=16352"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/categories?post=16352"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/tags?post=16352"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}