{"id":12545,"date":"2025-05-31T08:10:48","date_gmt":"2025-05-31T08:10:48","guid":{"rendered":"https:\/\/yaveni.com\/blog\/?p=12545"},"modified":"2025-05-31T08:10:57","modified_gmt":"2025-05-31T08:10:57","slug":"which-element-indicated-by-letter-on-the-periodic-table-above-contains-one-f-electron","status":"publish","type":"post","link":"https:\/\/gaviki.com\/blog\/which-element-indicated-by-letter-on-the-periodic-table-above-contains-one-f-electron\/","title":{"rendered":"Which element, indicated by letter on the periodic table above, contains one f electron"},"content":{"rendered":"\n<p>Which element, indicated by letter on the periodic table above, contains one f electron?<\/p>\n\n\n\n<p>A) A<\/p>\n\n\n\n<p>B) B<\/p>\n\n\n\n<p>C) C<\/p>\n\n\n\n<p>D) D<\/p>\n\n\n\n<p><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-vivid-cyan-blue-color\"><strong>The correct answer and explanation is :<\/strong><\/mark><\/p>\n\n\n\n<p>It looks like you&#8217;re referring to a periodic table image with labeled elements by letters (A, B, C, D), but I don\u2019t see the image attached here. To answer which element contains <strong>one f electron<\/strong>, I need to clarify a bit about the f block and the electronic configuration of elements.<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\">Understanding the f-electrons and the periodic table:<\/h3>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>f-electrons<\/strong> are electrons in the <strong>f orbitals<\/strong>, which are characteristic of the <strong>lanthanide<\/strong> and <strong>actinide<\/strong> series.<\/li>\n\n\n\n<li>The f-block elements are located in <strong>periods 6 and 7<\/strong>, between groups 3 and 4.<\/li>\n\n\n\n<li>The first f electron appears at <strong>lanthanum (La)<\/strong> or <strong>cerium (Ce)<\/strong> in the lanthanide series, depending on interpretation.<\/li>\n\n\n\n<li>The electron configuration for the first lanthanide with one f electron is typically <strong>[Xe] 6s\u00b2 5d\u00b9 4f\u00b9<\/strong> or <strong>[Xe] 6s\u00b2 4f\u00b9 5d\u00b9<\/strong> depending on subtle variations, but practically cerium (Ce) is considered the first to start filling the 4f orbital.<\/li>\n<\/ul>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\">Which element contains <strong>one f electron<\/strong>?<\/h3>\n\n\n\n<ul class=\"wp-block-list\">\n<li>The element with <strong>one f electron<\/strong> is the one starting the filling of the f orbitals in the lanthanide series: <strong>Cerium (Ce)<\/strong>.<\/li>\n\n\n\n<li>Cerium\u2019s electron configuration: [Xe]\u20096s2\u20094f1\u20095d1\\mathrm{[Xe]\\, 6s^2\\, 4f^1\\, 5d^1}<\/li>\n\n\n\n<li>Thus, Cerium contains exactly <strong>one electron in the 4f subshell<\/strong>.<\/li>\n<\/ul>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\">If your letter choices correspond to:<\/h3>\n\n\n\n<ul class=\"wp-block-list\">\n<li>A = Lanthanum (La) \u2014 typically 4f^0 (no f electron in La)<\/li>\n\n\n\n<li>B = Cerium (Ce) \u2014 4f^1 (one f electron)<\/li>\n\n\n\n<li>C = Praseodymium (Pr) \u2014 4f^3 (more than one f electron)<\/li>\n\n\n\n<li>D = Neodymium (Nd) \u2014 4f^4 (more than one f electron)<\/li>\n<\/ul>\n\n\n\n<p>Then the correct answer would be <strong>B (Cerium)<\/strong>.<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\">Explanation in detail (300 words):<\/h3>\n\n\n\n<p>In the periodic table, elements are arranged by increasing atomic number and grouped according to their electron configurations. The <strong>f-block<\/strong> elements, which include the lanthanides and actinides, are characterized by filling their <strong>f orbitals<\/strong>. The filling of the f orbitals starts with the lanthanide series, which begins after lanthanum (La, atomic number 57).<\/p>\n\n\n\n<p>Lanthanum itself has an electron configuration that does not include electrons in the 4f orbital, often written as [Xe]\u20095d1\u20096s2\\mathrm{[Xe]\\, 5d^1\\, 6s^2}, meaning the f orbitals remain empty here. The very next element, <strong>cerium (Ce)<\/strong>, starts the filling of the 4f orbital. Cerium has one electron in the 4f subshell, with the electron configuration [Xe]\u20096s2\u20094f1\u20095d1\\mathrm{[Xe]\\, 6s^2\\, 4f^1\\, 5d^1}. This marks the first appearance of f-electrons in the periodic table.<\/p>\n\n\n\n<p>After cerium, other lanthanides fill the 4f orbitals with increasing numbers of electrons: praseodymium has three 4f electrons, neodymium has four, and so on, filling up to fourteen f electrons in total for the last lanthanide, lutetium.<\/p>\n\n\n\n<p>Identifying which element contains exactly <strong>one f electron<\/strong> is essential in understanding the chemistry and electronic structure of the f-block elements. Cerium\u2019s unique position makes it the first element with an f electron, impacting its chemical properties and behavior in comparison to lanthanum, which has none.<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<p><strong>Summary:<\/strong><br>The element with <strong>one f electron<\/strong> is the first lanthanide to start filling the 4f orbital \u2014 <strong>Cerium (Ce)<\/strong>, corresponding to choice <strong>B<\/strong> in your question<\/p>\n","protected":false},"excerpt":{"rendered":"<p>Which element, indicated by letter on the periodic table above, contains one f electron? A) A B) B C) C D) D The correct answer and explanation is : It looks like you&#8217;re referring to a periodic table image with labeled elements by letters (A, B, C, D), but I don\u2019t see the image attached [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[],"tags":[],"class_list":["post-12545","post","type-post","status-publish","format-standard","hentry"],"_links":{"self":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/12545","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/comments?post=12545"}],"version-history":[{"count":1,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/12545\/revisions"}],"predecessor-version":[{"id":12546,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/12545\/revisions\/12546"}],"wp:attachment":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/media?parent=12545"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/categories?post=12545"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/tags?post=12545"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}