Which point, A or B, has a larger electric potential? What is the potential difference between A and B? Assume that E=1200V/m .
The correct answer and explanation is:
To determine which point, A or B, has a larger electric potential and the potential difference between them, we need to know:
- The direction of the electric field (E),
- The relative position of points A and B along the electric field.
Since the question doesn’t specify the direction or orientation of A and B, let’s assume a common scenario where:
- Points A and B lie along a straight line in the direction of the electric field.
- The electric field E=1200 V/mE = 1200 \, \text{V/m} points from A to B, which is the conventional direction of the electric field (from higher potential to lower potential).
Step 1: Direction of Electric Field and Potential
The electric field always points from higher to lower potential.
So if the field points from A to B, then:
- Point A has the higher potential.
- Point B has the lower potential.
Step 2: Potential Difference Calculation
The potential difference (ΔV\Delta V) between two points in a uniform electric field is given by: ΔV=VB−VA=−E⋅d\Delta V = V_B – V_A = -E \cdot d
Where:
- E=1200 V/mE = 1200 \, \text{V/m},
- dd is the distance between A and B along the field direction,
- The negative sign shows that potential decreases in the direction of the field.
If the distance between A and B is, say, 0.5 meters, then: ΔV=−1200⋅0.5=−600 V\Delta V = -1200 \cdot 0.5 = -600 \, \text{V}
So:
- VB=VA−600 VV_B = V_A – 600 \, \text{V}
- The potential difference is 600 volts,
- And point A has the higher electric potential.
✅ Final Answer:
- Point A has a larger electric potential.
- The potential difference between A and B is 600 volts, assuming a 0.5 m separation along the field direction.
If a different distance is given, simply multiply it by 1200 V/m to get the potential difference.