What is the balanced equation for copper (II) hydroxide + acetic acid (HC2H3O2) and what is it’s reaction, single, or double replacement.
The correct answer and explanation is:
The balanced chemical equation for the reaction between copper (II) hydroxide and acetic acid is: Cu(OH)2(aq)+2HC2H3O2(aq)→Cu(C2H3O2)2(aq)+2H2O(l)\text{Cu(OH)}_2 (aq) + 2 \text{HC}_2\text{H}_3\text{O}_2 (aq) \rightarrow \text{Cu(C}_2\text{H}_3\text{O}_2)_2 (aq) + 2 \text{H}_2\text{O} (l)
This reaction is a double replacement reaction. Here’s an explanation:
Reaction Type:
In a double replacement reaction, the cations and anions from the two reactants exchange places to form new compounds. In this case:
- The copper (II) cation (Cu²⁺) from copper (II) hydroxide combines with the acetate anion (C₂H₃O₂⁻) from acetic acid to form copper (II) acetate.
- The hydroxide anion (OH⁻) from copper (II) hydroxide combines with hydrogen ions (H⁺) from acetic acid to form water.
Reaction Explanation:
Copper (II) hydroxide (Cu(OH)₂) is an inorganic compound, and acetic acid (HC₂H₃O₂) is a weak acid that is commonly found in vinegar. When these two react, the hydroxide ions (OH⁻) from the copper (II) hydroxide react with the hydrogen ions (H⁺) from the acetic acid to form water (H₂O). Meanwhile, the copper (Cu²⁺) ion from copper (II) hydroxide combines with the acetate ions (C₂H₃O₂⁻) to form copper (II) acetate, a soluble salt. The result is the formation of copper (II) acetate and water.
Balancing the Equation:
- Copper (II) hydroxide provides one copper ion and two hydroxide ions (OH⁻).
- Acetic acid provides two hydrogen ions (H⁺) and two acetate ions (C₂H₃O₂⁻).
- Each side of the equation is balanced in terms of mass and charge.
Conclusion:
The reaction is a double replacement because the ions from each reactant swap places to form new products. This is a typical type of reaction when an acid reacts with a base or hydroxide.