How many grams of sulfur tetrafluoride are present in 3.57 moles of this compound?
grams
The correct answer and explanation is :
To find out how many grams of sulfur tetrafluoride (SF₄) are present in 3.57 moles, we need to use the relationship between moles, mass, and molar mass.
Step 1: Find the molar mass of SF₄.
The molar mass of a compound is the sum of the atomic masses of all the atoms in the molecule.
- The atomic mass of sulfur (S) is approximately 32.07 g/mol.
- The atomic mass of fluorine (F) is approximately 18.998 g/mol.
Sulfur tetrafluoride (SF₄) consists of one sulfur atom and four fluorine atoms. So, the molar mass of SF₄ is calculated as:
$$
\text{Molar mass of SF₄} = \text{Molar mass of S} + 4 \times \text{Molar mass of F}
$$
$$
\text{Molar mass of SF₄} = 32.07 \, \text{g/mol} + 4 \times 18.998 \, \text{g/mol}
$$
$$
\text{Molar mass of SF₄} = 32.07 \, \text{g/mol} + 75.992 \, \text{g/mol}
$$
$$
\text{Molar mass of SF₄} = 108.062 \, \text{g/mol}
$$
Step 2: Use the number of moles to calculate the mass.
The mass of a substance can be calculated using the formula:
$$
\text{Mass} = \text{Moles} \times \text{Molar mass}
$$
Given that we have 3.57 moles of SF₄:
$$
\text{Mass of SF₄} = 3.57 \, \text{moles} \times 108.062 \, \text{g/mol}
$$
$$
\text{Mass of SF₄} = 386.47 \, \text{g}
$$
Final Answer:
The mass of 3.57 moles of sulfur tetrafluoride (SF₄) is 386.47 grams.
Explanation:
This calculation is based on converting moles to grams by using the molar mass of the compound. Moles give the number of molecules or formula units, and the molar mass tells us how much one mole of those molecules weighs in grams. By multiplying the number of moles by the molar mass, we obtain the mass in grams.