How many grams of sulfur dioxide are present in 2.29 moles of this compound?
The correct answer and explanation is:
To find the number of grams of sulfur dioxide (SO₂) in 2.29 moles, use the formula:
Mass (g) = Moles × Molar Mass
The molar mass of sulfur dioxide (SO₂) is calculated by adding the atomic masses of its elements:
- Sulfur (S) = 32.07 g/mol
- Oxygen (O) = 16.00 g/mol
- SO₂ has 1 sulfur atom and 2 oxygen atoms
So:
Molar mass of SO₂ = 32.07 + (2 × 16.00) = 32.07 + 32.00 = 64.07 g/mol
Now multiply:
Mass = 2.29 mol × 64.07 g/mol = 146.72 grams
Final Answer: 146.72 grams
Explanation:
To convert from moles to grams, it is necessary to use the concept of molar mass. A mole is a unit used to count particles such as atoms or molecules. In this case, the compound is sulfur dioxide (SO₂), a molecule consisting of one sulfur atom and two oxygen atoms.
The molar mass acts like a conversion factor between moles and grams. Every substance has a unique molar mass based on its chemical composition. For sulfur dioxide, adding the atomic masses of one sulfur atom and two oxygen atoms gives a molar mass of 64.07 grams per mole. This means one mole of SO₂ weighs 64.07 grams.
To find out how much 2.29 moles of SO₂ weigh, multiply the number of moles by the molar mass. This yields 146.72 grams. The result indicates the total mass of SO₂ present in 2.29 moles of the compound. This approach is standard in chemistry and helps convert between the measurable amount in grams and the chemical quantity in moles. This type of calculation is essential for preparing solutions, performing reactions, and analyzing substances in chemical studies.