How many grams of potassium oxide (K2O) are there in 0.630 mol?
The Correct Answer and Explanation is:
To calculate how many grams of potassium oxide (K₂O) are in 0.630 mol, we need to follow a few steps:
Step 1: Find the molar mass of potassium oxide (K₂O)
The molar mass of a compound is the sum of the atomic masses of all its elements, which we can find on the periodic table.
- Potassium (K) has an atomic mass of about 39.1 g/mol.
- Oxygen (O) has an atomic mass of about 16.0 g/mol.
So, the molar mass of K₂O is:(2×39.1 g/mol)+(1×16.0 g/mol)=78.2 g/mol+16.0 g/mol=94.2 g/mol.(2 \times 39.1 \, \text{g/mol}) + (1 \times 16.0 \, \text{g/mol}) = 78.2 \, \text{g/mol} + 16.0 \, \text{g/mol} = 94.2 \, \text{g/mol}.(2×39.1g/mol)+(1×16.0g/mol)=78.2g/mol+16.0g/mol=94.2g/mol.
Step 2: Use the formula for moles to calculate the mass
The number of grams in a given number of moles is calculated by multiplying the number of moles by the molar mass:Mass=Moles×Molar mass\text{Mass} = \text{Moles} \times \text{Molar mass}Mass=Moles×Molar mass
Substitute the values:Mass=0.630 mol×94.2 g/mol\text{Mass} = 0.630 \, \text{mol} \times 94.2 \, \text{g/mol}Mass=0.630mol×94.2g/molMass=59.3 g.\text{Mass} = 59.3 \, \text{g}.Mass=59.3g.
Step 3: Final Answer
Therefore, there are 59.3 grams of potassium oxide (K₂O) in 0.630 mol.
Explanation
The molar mass of potassium oxide is a crucial step in converting moles to grams. By multiplying the amount of moles by the molar mass, we essentially find out how much mass corresponds to the given number of moles. In this case, 0.630 mol of K₂O weighs 59.3 grams.
