How many chloride ions are in 3.3 moles of CaCl2?
The Correct Answer and Explanation is:
Correct Answer:
There are 3.97 × 10²⁴ chloride ions in 3.3 moles of CaCl₂.
Step-by-Step Explanation:
To determine the number of chloride ions present in 3.3 moles of calcium chloride (CaCl₂), follow these steps:
Step 1: Understand the Formula
The chemical formula for calcium chloride is CaCl₂, meaning:
- Each formula unit contains 1 calcium ion (Ca²⁺)
- Each formula unit contains 2 chloride ions (Cl⁻)
Thus, for every mole of CaCl₂, there are 2 moles of chloride ions.
Step 2: Calculate the Moles of Chloride Ions
Given:
- You have 3.3 moles of CaCl₂
- Each mole of CaCl₂ produces 2 moles of Cl⁻
So:Moles of Cl⁻=3.3 moles of CaCl₂×2=6.6 moles of Cl⁻\text{Moles of Cl⁻} = 3.3 \, \text{moles of CaCl₂} \times 2 = 6.6 \, \text{moles of Cl⁻}Moles of Cl⁻=3.3moles of CaCl₂×2=6.6moles of Cl⁻
Step 3: Convert Moles to Number of Ions
To convert moles to individual ions, use Avogadro’s number, which is:6.022×1023 entities per mole6.022 \times 10^{23} \, \text{entities per mole}6.022×1023entities per mole
So:Number of Cl⁻ ions=6.6 moles×6.022×1023=3.97452×1024 ions\text{Number of Cl⁻ ions} = 6.6 \, \text{moles} \times 6.022 \times 10^{23} = 3.97452 \times 10^{24} \, \text{ions}Number of Cl⁻ ions=6.6moles×6.022×1023=3.97452×1024ions
Rounding appropriately:Number of Cl⁻ ions≈3.97×1024\text{Number of Cl⁻ ions} \approx 3.97 \times 10^{24}Number of Cl⁻ ions≈3.97×1024
Final Answer:
There are approximately 3.97 × 10²⁴ chloride ions in 3.3 moles of calcium chloride.
This problem illustrates the relationship between moles, chemical formulas, and Avogadro’s number, which is fundamental in stoichiometric calculations in chemistry.
