How many atoms are one 1.4 mil of phosphorus trifluoride (PF3)
The correct answer and explanation is:
To determine the number of atoms in 1.4 millimoles (mil) of phosphorus trifluoride (PF₃), follow these steps:
Step 1: Understand the Molecular Composition of PF₃
Phosphorus trifluoride (PF₃) is a molecular compound made up of one phosphorus (P) atom and three fluorine (F) atoms. Therefore, each molecule of PF₃ contains:
- 1 phosphorus atom
- 3 fluorine atoms
Step 2: Find the Number of Molecules in 1.4 millimoles
Since 1 mole of any substance contains Avogadro’s number of particles (6.022 × 10²³), we need to calculate the number of molecules in 1.4 millimoles of PF₃. First, convert millimoles to moles: 1.4 mil=1.4×10−3 mol1.4 \, \text{mil} = 1.4 \times 10^{-3} \, \text{mol}
Now, calculate the number of molecules in 1.4 millimoles: 1.4×10−3 mol×(6.022×1023 molecules/mol)=8.428×1020 molecules1.4 \times 10^{-3} \, \text{mol} \times (6.022 \times 10^{23} \, \text{molecules/mol}) = 8.428 \times 10^{20} \, \text{molecules}
Step 3: Calculate the Total Number of Atoms
Since each molecule of PF₃ contains 1 phosphorus atom and 3 fluorine atoms, there are 4 atoms per molecule of PF₃. Therefore, to find the total number of atoms, multiply the number of molecules by the number of atoms per molecule: 8.428×1020 molecules×4 atoms/molecule=3.371×1021 atoms8.428 \times 10^{20} \, \text{molecules} \times 4 \, \text{atoms/molecule} = 3.371 \times 10^{21} \, \text{atoms}
Final Answer:
The number of atoms in 1.4 millimoles of PF₃ is approximately 3.37 × 10²¹ atoms.
Explanation:
This calculation uses basic principles of mole concept and Avogadro’s number to convert between moles, molecules, and atoms. By understanding the molecular composition of PF₃ and recognizing the relationship between moles and particles, we can determine the total number of atoms in a given amount of substance.