Find the exact value of the trigonometric expression without the use of a calculator. sin(pi/12) cos(7pi/12) + cos(pi/12) sin(7pi/12) =

The Correct Answer and Explanation is:

Correct Answer:

We are asked to find the exact value of:sin⁡(π12)cos⁡(7π12)+cos⁡(π12)sin⁡(7π12)\sin\left(\frac{\pi}{12}\right)\cos\left(\frac{7\pi}{12}\right) + \cos\left(\frac{\pi}{12}\right)\sin\left(\frac{7\pi}{12}\right)sin(12π​)cos(127π​)+cos(12π​)sin(127π​)

This expression matches the identity for the sine of a sum of angles:sin⁡(A+B)=sin⁡(A)cos⁡(B)+cos⁡(A)sin⁡(B)\sin(A + B) = \sin(A)\cos(B) + \cos(A)\sin(B)sin(A+B)=sin(A)cos(B)+cos(A)sin(B)

In this case:

  • A=π12A = \frac{\pi}{12}A=12π​
  • B=7π12B = \frac{7\pi}{12}B=127π​

Thus, applying the identity:sin⁡(π12+7π12)=sin⁡(8π12)=sin⁡(2π3)\sin\left(\frac{\pi}{12} + \frac{7\pi}{12}\right) = \sin\left(\frac{8\pi}{12}\right) = \sin\left(\frac{2\pi}{3}\right)sin(12π​+127π​)=sin(128π​)=sin(32π​)

We know that:sin⁡(2π3)=sin⁡(π−π3)\sin\left(\frac{2\pi}{3}\right) = \sin\left(\pi – \frac{\pi}{3}\right)sin(32π​)=sin(π−3π​)

Using the identity for sine of supplementary angles:sin⁡(π−x)=sin⁡(x)\sin(\pi – x) = \sin(x)sin(π−x)=sin(x)

Therefore:sin⁡(2π3)=sin⁡(π3)=32\sin\left(\frac{2\pi}{3}\right) = \sin\left(\frac{\pi}{3}\right) = \frac{\sqrt{3}}{2}sin(32π​)=sin(3π​)=23​​

Final exact value:32\boxed{\frac{\sqrt{3}}{2}}23​​​


Detailed Explanation:

This problem tests knowledge of trigonometric identities and simplifications involving radians. The given expression fits the standard identity for the sine of a sum of angles, which simplifies the calculation significantly.

First, identify the structure:

  • The expression has sin⁡\sinsin of one angle multiplied by cos⁡\coscos of another and vice versa, which is the exact form of sin⁡(A+B)\sin(A + B)sin(A+B).
  • Plug in the angles: A=π12A = \frac{\pi}{12}A=12π​ and B=7π12B = \frac{7\pi}{12}B=127π​.
  • Their sum is 8π12=2π3\frac{8\pi}{12} = \frac{2\pi}{3}128π​=32π​.

To find sin⁡(2π3)\sin\left(\frac{2\pi}{3}\right)sin(32π​), note that 2π3\frac{2\pi}{3}32π​ lies in the second quadrant where sine is positive. Using reference angles, sin⁡(2π3)\sin(\frac{2\pi}{3})sin(32π​) simplifies to sin⁡(π3)\sin(\frac{\pi}{3})sin(3π​).

The known exact value for sin⁡(π3)\sin(\frac{\pi}{3})sin(3π​) is 32\frac{\sqrt{3}}{2}23​​.

Thus, without needing a calculator, the expression simplifies directly to 32\frac{\sqrt{3}}{2}23​​.

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