Ba2+ is the chemical symbol for Barium ion. The charge of the ion is 2+. The symbol for Vanadium is V. The atomic number of Vanadium is 23. The atomic number of Barium is 56
The Correct Answer and Explanation is:
The correct answer to the problem is Ce,4+.
Here’s a full explanation:
To determine the chemical symbol and charge of the ion, we start by identifying the number of protons. The ion has 58 protons, which is the atomic number of Cerium. This means the chemical symbol is Ce.
Next, we calculate the charge of the ion by comparing the number of protons to the number of electrons. Protons are positively charged, and electrons are negatively charged. The ion contains 54 electrons. The net charge is the result of the difference between the number of protons and electrons:
- Net charge = Number of protons – Number of electrons
- Net charge = 58 – 54 = +4
Since the ion has four more protons than electrons, it has a positive charge of 4. The notation for this in the required format is Ce,4+.
The number of neutrons, which in this case is 84, does not affect the chemical identity or the charge. Neutrons contribute only to the atomic mass and to isotope variations. They do not change the overall electric charge of the atom or ion.
To summarize, 58 protons identify the element as Cerium. The deficit of four electrons means the ion carries a 4+ charge. This creates the final answer: Ce,4+, formatted as required by the problem.
This kind of question reinforces the importance of understanding atomic structure. It connects basic chemistry concepts such as atomic number, ion charge, and electron-proton balance. Once you master these principles, you can decode most questions about ions with confidence.
