Aluminium is extracted from aluminium oxide according to the equation: 2Al2O3 → 4Al + 3O2. Calculate the mass of aluminium produced from 1000g of aluminium oxide.
The Correct Answer and Explanation is:
Correct Answer:
The mass of aluminium produced from 1000 grams of aluminium oxide is 529.1 grams.
Step-by-Step Calculation:
1. Write the balanced equation:2Al2O3→4Al+3O22Al_2O_3 \rightarrow 4Al + 3O_22Al2O3→4Al+3O2
2. Find the molar masses:
- Molar mass of aluminium (Al) = 27 g/mol
- Molar mass of oxygen (O) = 16 g/mol
- Molar mass of aluminium oxide (Al₂O₃) = (2 × 27) + (3 × 16) = 54 + 48 = 102 g/mol
3. Use the mole ratio from the equation:
- 2 moles of Al₂O₃ produce 4 moles of Al
- Mass of 2 moles of Al₂O₃ = 2 × 102 = 204 g
- Mass of 4 moles of Al = 4 × 27 = 108 g
So, from 204 g of Al₂O₃, we get 108 g of Al.
4. Calculate mass of aluminium from 1000 g of aluminium oxide using proportion:108 g Al204 g Al2O3=x g Al1000 g Al2O3\frac{108 \, g \, Al}{204 \, g \, Al_2O_3} = \frac{x \, g \, Al}{1000 \, g \, Al_2O_3}204gAl2O3108gAl=1000gAl2O3xgAl
Solve for x:x=108×1000204=529.41 gx = \frac{108 \times 1000}{204} = 529.41 \, gx=204108×1000=529.41g
Thus, approximately 529.1 grams of aluminium are produced.
Explanation:
Aluminium is extracted from aluminium oxide by electrolysis, where aluminium oxide is broken down into pure aluminium metal and oxygen gas. The process relies on a known chemical relationship described by the balanced equation, which ensures the correct amount of reactants and products.
The molar mass values allow us to convert between grams and moles, making it possible to predict how much aluminium can be obtained from a specific mass of aluminium oxide. By using stoichiometry, we relate the known mass of the compound to the desired mass of aluminium.
In this case, 1000 grams of aluminium oxide yields 529.1 grams of aluminium when the reaction proceeds completely without any waste
