Draw the molecular orbital diagram of CS. Determine bond order, magnetism, spin multiplicity, and HOMO/LUMO.
The Correct Answer and Explanation is:
To draw the molecular orbital diagram of carbon monosulfide (CS), we need to consider the bonding between carbon (C) and sulfur (S). CS is a diatomic molecule and its molecular orbital diagram involves the combination of atomic orbitals of carbon and sulfur atoms.
Steps for constructing the molecular orbital diagram:
- Determine the electron configuration of atoms:
- Carbon (C): 1s² 2s² 2p²
- Sulfur (S): 1s² 2s² 2p⁶ 3s² 3p⁴
- Orbital interactions:
- The lowest-energy molecular orbitals are formed from the combination of the atomic 2s and 3s orbitals, followed by the 2p and 3p orbitals.
- Fill the molecular orbitals:
The molecular orbitals are arranged in increasing energy order (for a heteronuclear molecule like CS):- σ(2s), σ*(2s)
- σ(3s), σ*(3s)
- π(2p), π*(2p) (degenerate, higher energy)
- σ(2p), σ*(2p)
- Filling the molecular orbitals:
- 2 electrons in σ(2s) (bonding)
- 2 electrons in σ*(2s) (antibonding)
- 2 electrons in σ(3s) (bonding)
- 2 electrons in σ*(3s) (antibonding)
- 4 electrons in π(2p) (bonding)
- 2 electrons in π*(2p) (antibonding)
- Determine bond order:
- Bond order = (number of bonding electrons – number of antibonding electrons) / 2
- Bond order = (2 + 2 + 4) – (2 + 2) / 2 = 4 / 2 = 2
- Magnetism:
CS has no unpaired electrons in its molecular orbitals, meaning it is diamagnetic. - Spin multiplicity:
The spin multiplicity is calculated as 2S + 1, where S is the total spin quantum number. Since all electrons are paired, S = 0, and the spin multiplicity is 1 (singlet). - HOMO and LUMO:
- The Highest Occupied Molecular Orbital (HOMO) is the π*(2p) orbital.
- The Lowest Unoccupied Molecular Orbital (LUMO) is the σ*(2p) orbital.
Summary:
- Bond order: 2
- Magnetism: Diamagnetic
- Spin multiplicity: 1 (singlet)
- HOMO: π*(2p)
- LUMO: σ*(2p)
