calculate the theoretical yield of cyclohexanone from 16 ml of cyclohexanol. molecular weight of cyclohexanol = 100.26 g, molecular weight of cyclohexanone = 98.14 g, and the density of cyclohexanol = 0.96 g/ml
The Correct Answer and Explanation is:
To calculate the theoretical yield of cyclohexanone from 16 mL of cyclohexanol, we first need to follow these steps:
Step 1: Calculate the mass of cyclohexanol
The density of cyclohexanol is 0.96 g/mL. Therefore, the mass of 16 mL of cyclohexanol is:Mass of cyclohexanol=Density×Volume\text{Mass of cyclohexanol} = \text{Density} \times \text{Volume}Mass of cyclohexanol=Density×VolumeMass of cyclohexanol=0.96 g/mL×16 mL=15.36 g\text{Mass of cyclohexanol} = 0.96 \, \text{g/mL} \times 16 \, \text{mL} = 15.36 \, \text{g}Mass of cyclohexanol=0.96g/mL×16mL=15.36g
Step 2: Convert the mass of cyclohexanol to moles
The molecular weight of cyclohexanol is 100.26 g/mol. To convert the mass to moles, use the formula:Moles of cyclohexanol=Mass of cyclohexanolMolecular weight of cyclohexanol\text{Moles of cyclohexanol} = \frac{\text{Mass of cyclohexanol}}{\text{Molecular weight of cyclohexanol}}Moles of cyclohexanol=Molecular weight of cyclohexanolMass of cyclohexanolMoles of cyclohexanol=15.36 g100.26 g/mol=0.1534 mol\text{Moles of cyclohexanol} = \frac{15.36 \, \text{g}}{100.26 \, \text{g/mol}} = 0.1534 \, \text{mol}Moles of cyclohexanol=100.26g/mol15.36g=0.1534mol
Step 3: Determine the moles of cyclohexanone formed
In this reaction, cyclohexanol undergoes a dehydration process (typically catalytic dehydrogenation) to form cyclohexanone. Assuming a 100% conversion rate and a 1:1 molar ratio between cyclohexanol and cyclohexanone, the moles of cyclohexanone produced will be the same as the moles of cyclohexanol.Moles of cyclohexanone=0.1534 mol\text{Moles of cyclohexanone} = 0.1534 \, \text{mol}Moles of cyclohexanone=0.1534mol
Step 4: Convert moles of cyclohexanone to mass
Now that we know the moles of cyclohexanone, we can calculate its mass. The molecular weight of cyclohexanone is 98.14 g/mol. Use the following formula:Mass of cyclohexanone=Moles of cyclohexanone×Molecular weight of cyclohexanone\text{Mass of cyclohexanone} = \text{Moles of cyclohexanone} \times \text{Molecular weight of cyclohexanone}Mass of cyclohexanone=Moles of cyclohexanone×Molecular weight of cyclohexanoneMass of cyclohexanone=0.1534 mol×98.14 g/mol=15.04 g\text{Mass of cyclohexanone} = 0.1534 \, \text{mol} \times 98.14 \, \text{g/mol} = 15.04 \, \text{g}Mass of cyclohexanone=0.1534mol×98.14g/mol=15.04g
Step 5: Conclusion
Thus, the theoretical yield of cyclohexanone from 16 mL of cyclohexanol is 15.04 g, assuming complete conversion of cyclohexanol to cyclohexanone with no side reactions.
