The atmospheric pressure in Denver, Colorado, is usually about 84.0 kPa

The atmospheric pressure in Denver, Colorado, is usually about 84.0 kPa. What is this pressure in atm and torr units? 71. At an ocean depth of 250 feet, the pressure is about 8.4 atm. Convert the pressure to mm Hg and kPa units.

The Correct Answer and Explanation is:

Let’s solve the two problems one by one.

1. Atmospheric pressure in Denver (84.0 kPa) to atm and torr:

To convert pressure units, we need to use the following relationships:

• 1 atm = 101.3 kPa
• 1 atm = 760 torr

Conversion from kPa to atm:

To convert from kilopascals (kPa) to atmospheres (atm), we use the formula:Pressure in atm=Pressure in kPa101.3\text{Pressure in atm} = \frac{\text{Pressure in kPa}}{101.3}Pressure in atm=101.3Pressure in kPa​

Substituting the given pressure (84.0 kPa):Pressure in atm=84.0101.3≈0.829 atm\text{Pressure in atm} = \frac{84.0}{101.3} \approx 0.829 \, \text{atm}Pressure in atm=101.384.0​≈0.829atm

Conversion from kPa to torr:

Next, to convert from kPa to torr, we use the relationship:Pressure in torr=Pressure in kPa×760101.3\text{Pressure in torr} = \frac{\text{Pressure in kPa} \times 760}{101.3}Pressure in torr=101.3Pressure in kPa×760​

Substituting the given pressure:Pressure in torr=84.0×760101.3≈628.3 torr\text{Pressure in torr} = \frac{84.0 \times 760}{101.3} \approx 628.3 \, \text{torr}Pressure in torr=101.384.0×760​≈628.3torr

So, the pressure in Denver is approximately:

• 0.829 atm
• 628.3 torr

2. Ocean depth pressure of 8.4 atm to mm Hg and kPa:

Now, let’s convert the pressure at an ocean depth of 250 feet (8.4 atm) to mm Hg and kPa.

Conversion from atm to mm Hg:

Using the relationship:1 atm=760 mm Hg1 \, \text{atm} = 760 \, \text{mm Hg}1atm=760mm Hg

We multiply the given pressure in atm by 760:Pressure in mm Hg=8.4×760=6384 mm Hg\text{Pressure in mm Hg} = 8.4 \times 760 = 6384 \, \text{mm Hg}Pressure in mm Hg=8.4×760=6384mm Hg

Conversion from atm to kPa:

To convert from atm to kPa, we use:1 atm=101.3 kPa1 \, \text{atm} = 101.3 \, \text{kPa}1atm=101.3kPa

So:Pressure in kPa=8.4×101.3=850.9 kPa\text{Pressure in kPa} = 8.4 \times 101.3 = 850.9 \, \text{kPa}Pressure in kPa=8.4×101.3=850.9kPa

Thus, the pressure at a depth of 250 feet is approximately:

• 6384 mm Hg
• 850.9 kPa

Summary:

• The atmospheric pressure in Denver (84.0 kPa) is about 0.829 atm and 628.3 torr.
• The pressure at an ocean depth of 250 feet (8.4 atm) is about 6384 mm Hg and 850.9 kPa.