The infrared (IR) spectrum of an organic compound is shown below % Transmittance 100 50 0 4000 3000 2000 1500 1000 500 Wavenumber / cm
(d) Deduce the structures of two possible isomers of propanoic acid consistent with the IR spectrum.

The Correct Answer and Explanation is:

To answer part (d) — deducing two possible isomers of propanoic acid consistent with the IR spectrum — we must first analyze the spectrum provided and identify the key absorption peaks that indicate functional groups present.

Key IR Peaks and Interpretation:

  1. Broad absorption around 2500–3300 cm⁻¹:
    • This is characteristic of the O–H stretch of a carboxylic acid. The broad and irregular shape supports this interpretation.
  2. Sharp peak near 1710 cm⁻¹:
    • This corresponds to the C=O stretching vibration typical of carboxylic acids.
  3. Multiple peaks in the fingerprint region (below 1500 cm⁻¹):
    • These are consistent with various C–H bending vibrations and other molecular features. While not individually diagnostic, they help confirm the molecular structure.

Conclusion:

The compound is a carboxylic acid, consistent with propanoic acid (CH₃CH₂COOH). Isomers of propanoic acid are compounds with the same molecular formula (C₃H₆O₂) but different structures.

Two Possible Isomers Consistent with the IR Spectrum:

  1. Propanoic acid (CH₃CH₂COOH):
    • A straight-chain carboxylic acid.
    • Shows both O–H and C=O stretches.
    • No branching or other functional groups.
  2. 2-hydroxypropanal (CH₃CH(OH)CHO):
    • While technically not a positional isomer of a carboxylic acid, it is a constitutional isomer with the same molecular formula.
    • Contains an aldehyde (C=O around 1720 cm⁻¹) and hydroxyl (O–H around 3300 cm⁻¹).
    • However, this structure may not match as well due to the absence of a broad, strong carboxylic O–H stretch.

A better second candidate:

Methyl formate (HCOOCH₃):

  • An ester, another isomer of C₃H₆O₂.
  • Esters show a C=O stretch around 1740 cm⁻¹ and a C–O stretch near 1200 cm⁻¹.
  • However, the broad O–H peak is absent in esters, so it’s less likely given the spectrum.

Final answer:

  • Propanoic acid (CH₃CH₂COOH)
  • 2-hydroxypropanoic acid (lactic acid, CH₃CH(OH)COOH) — a plausible isomer with similar O–H and C=O signals, consistent with the IR spectrum.

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