6x + 4y = 6, 6x + 2y = 12

The Correct Answer and Explanation is:

Correct Answer:

We are to solve the system of equations:

1) 6x+4y=66x + 4y = 66x+4y=6
2) 6x+2y=126x + 2y = 126x+2y=12

Step 1: Eliminate one variable using the elimination method

Subtract equation 2 from equation 1:(6x+4y)−(6x+2y)=6−12(6x + 4y) – (6x + 2y) = 6 – 12(6x+4y)−(6x+2y)=6−12

Simplifying:6x−6x+4y−2y=−66x – 6x + 4y – 2y = -66x−6x+4y−2y=−62y=−62y = -62y=−6

Divide both sides by 2:y=−3y = -3y=−3

Step 2: Substitute the value of yyy into one of the original equations

We use equation 2:6x+2y=126x + 2y = 126x+2y=12

Substitute y=−3y = -3y=−3:6x+2(−3)=126x + 2(-3) = 126x+2(−3)=12

Simplifying:6x−6=126x – 6 = 126x−6=12

Add 6 to both sides:6x=186x = 186x=18

Divide both sides by 6:x=3x = 3x=3

Final Solution:

x=3,y=−3x = 3, \quad y = -3x=3,y=−3

Explanation

To solve this system of linear equations, we use the elimination method, which involves eliminating one variable to simplify the system into a single-variable equation. We are given two linear equations involving xxx and yyy:

  1. 6x+4y=66x + 4y = 66x+4y=6
  2. 6x+2y=126x + 2y = 126x+2y=12

The first step is to eliminate xxx by subtracting equation 2 from equation 1. The xxx terms 6x6x6x cancel each other out, leaving us with:4y−2y=6−124y – 2y = 6 – 124y−2y=6−12

This simplifies to 2y=−62y = -62y=−6. Solving for yyy gives y=−3y = -3y=−3.

Once we have the value of yyy, we substitute it back into one of the original equations to find xxx. Using the second equation:6x+2y=126x + 2y = 126x+2y=12

Replacing yyy with −3-3−3:6x+2(−3)=126x + 2(-3) = 126x+2(−3)=12

This simplifies to:6x−6=126x – 6 = 126x−6=12

Adding 6 to both sides:6x=186x = 186x=18

Dividing both sides by 6:x=3x = 3x=3

Thus, the solution to the system is x=3x = 3x=3 and y=−3y = -3y=−3.

We can verify by substituting these values into both original equations to confirm they satisfy both, ensuring the solution is correct. This method is reliable for solving linear systems.

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