Check my work Click in the answer box to display choices: Choose the compound that matches the IR spectrum shown 100 L 50 88 4000 3500 3000 2500 2000 1500 1000 Wavenumber (cm-1) 500 B: HO D: E: OH The spectrum belongs to compound ((select)
The Correct Answer and Explanation is:
The compound that matches the IR spectrum is compound F.
Here’s a detailed explanation:
The IR spectrum features a broad absorption near 3300 cm⁻¹, which is a strong indicator of an O–H stretching vibration. This broadness is characteristic of hydrogen bonding, which is typically observed in alcohols and carboxylic acids. In addition to that, there’s a prominent sharp peak around 1700 cm⁻¹, representing a C=O stretching vibration that is common in carbonyl-containing compounds, such as aldehydes, ketones, esters, and carboxylic acids.
This dual presence of both an O–H stretch and a C=O stretch strongly suggests a carboxylic acid functional group. Carboxylic acids uniquely combine these two features in a single molecule. Among the given compounds, compound F is the only structure that contains both these functional groups.
The fingerprint region—spanning from roughly 1500 to 500 cm⁻¹—also supports this assignment. While this region is complex and often crowded with signals, the pattern seen in the spectrum aligns well with the skeletal vibrations expected in carboxylic acids.
By process of elimination, the other structures either lack a hydroxyl group, a carbonyl group, or both. Some may contain alcohols or ketones individually, but not both within a single molecule. This makes compound F the only one consistent with the signature IR absorptions seen.
In conclusion, the IR spectrum demonstrates the key traits of a carboxylic acid, and compound F is the only structure that satisfies those criteria. This match between functional group signals and molecular structure firmly confirms F as the correct compound.
