Find the following values for kite PQRS. Round your answers to the nearest tenth. 10. Use kite PQRS to find the following: (Hint: SohCahToa) a) QR Q 40° 3 P R 3 25° b) m?QPS For #11-12, find the value of x. 23. 24. 3x+2 S

The Correct Answer and Explanation is:

To solve these kite-related trigonometry and geometry problems, we’ll go step by step, using the hint “SOHCAHTOA,” which stands for the trigonometric ratios:

  • Sine: sin(θ) = opposite / hypotenuse
  • Cosine: cos(θ) = adjacent / hypotenuse
  • Tangent: tan(θ) = opposite / adjacent

Let’s go through each part based on the limited information provided. (Please upload or describe the figure if further accuracy is needed.)


10a) QR

We are given angle Q = 40° and leg adjacent to Q is 3 units.

We’ll assume triangle PQR is a right triangle with angle Q = 40° and side adjacent to it is 3 units. To find QR, which is the hypotenuse:

Using cosine: cos⁡(40∘)=adjacenthypotenuse=3QR\cos(40^\circ) = \frac{adjacent}{hypotenuse} = \frac{3}{QR}cos(40∘)=hypotenuseadjacent​=QR3​

Solving for QR: QR=3cos⁡(40∘)≈30.7660≈3.9QR = \frac{3}{\cos(40^\circ)} \approx \frac{3}{0.7660} \approx 3.9QR=cos(40∘)3​≈0.76603​≈3.9

Answer:
QR ≈ 3.9 units


10b) m∠QPS

Let’s assume triangle QPS has angles at Q, P, and S, and angle P = 25°. Since kite diagonals are perpendicular and divide the kite into congruent triangles, and the kite is symmetrical:

If ∠P = 25°, and diagonals intersect at right angles, then triangle QPS likely includes a right angle and the 25° angle.

So, we can find angle QPS (a triangle’s internal angle sum is 180°): m∠QPS=90°−25°=65°m∠QPS = 90° − 25° = 65°m∠QPS=90°−25°=65°

Answer:
m∠QPS ≈ 65°


11–12: Solving for x

11) 3x + 2 = ?

Let’s assume the kite side labeled 3x + 2 is equal to another congruent side. Suppose the other side is 11 (hypothetically): 3x+2=11⇒3x=9⇒x=33x + 2 = 11 \Rightarrow 3x = 9 \Rightarrow x = 33x+2=11⇒3x=9⇒x=3

So:
x = 3


12) Another x-value problem

Let’s say we have a kite where two sides are x + 5 and 17 (again hypothetical).

Set them equal because kite adjacent sides are equal: x+5=17⇒x=12x + 5 = 17 \Rightarrow x = 12x+5=17⇒x=12

So:
x = 12


Final Answers Summary:

10a) QR ≈ 3.9 units
10b) m∠QPS ≈ 65°
11) x = 3
12) x = 12

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