Can you pass an individual array element to a function in C

Can you pass an individual array element to a function in C ? If so, how? Specify the syntax.

The correct answer and explanation is:

Correct Answer:
Yes, you can pass an individual array element to a function in C by passing it just like a regular variable using its index.

Syntax Example:

#include <stdio.h>

// Function that takes an integer as an argument
void printElement(int element) {
    printf("Element is: %d\n", element);
}

int main() {
    int numbers[] = {10, 20, 30, 40, 50};
    
    // Pass the third element (index 2) to the function
    printElement(numbers[2]);

    return 0;
}

300-Word Explanation:

In the C programming language, an array is a collection of variables of the same type stored in contiguous memory locations. Each item in the array can be accessed individually using its index. Since each element of an array is essentially a variable of the same data type as the array, it can be passed to a function in the same way you pass a variable.

To pass an individual array element to a function, you use the array name followed by the index in square brackets, like arrayName[index]. This accesses the specific element and passes its value to the function. In this case, the function receives a copy of the value (pass-by-value).

For instance, in the code above, the numbers array is defined with five integers. The printElement() function is designed to take a single integer as its argument. When calling the function with numbers[2], the value 30 (the third element) is passed to the function, and it prints "Element is: 30".

This is different from passing the whole array to a function, which involves passing the address (pointer) of the first element and typically requires additional information like the size of the array.

In summary, passing a single array element is straightforward and treated just like passing any other variable. This is useful when a function only needs to operate on a single item and not the entire array.