Calculate phenotype frequencies in 5th generation. Record in Lab Data 5 Calculate allele frequencies in 5th generation. Record in Lab Data 6 Calculate genotype frequencies and number of moths in 5th generation. Record in Lab Data

The Correct Answer and Explanation is:

To generate the correct answer, I need specific data from your lab results — such as the number of each phenotype (e.g., light-colored vs. dark-colored moths), the total population in the 5th generation, or the counts of different genotypes (e.g., homozygous dominant, heterozygous, homozygous recessive). However, I can guide you through how to calculate phenotype frequencies, allele frequencies, and genotype frequencies with an explanation below.


Step-by-Step Guide and Example:

Assume in the 5th generation you have:

  • 200 moths total
  • 120 dark-colored moths
  • 80 light-colored moths

1. Phenotype Frequencies (Lab Data 5)

To calculate phenotype frequency:Frequency=Number of individuals with phenotypeTotal number of individuals\text{Frequency} = \frac{\text{Number of individuals with phenotype}}{\text{Total number of individuals}}Frequency=Total number of individualsNumber of individuals with phenotype​

  • Dark-colored:
    120200=0.60\frac{120}{200} = 0.60200120​=0.60
  • Light-colored:
    80200=0.40\frac{80}{200} = 0.4020080​=0.40

2. Genotype Frequencies and Numbers (Lab Data 6)

Assume:

  • Dark moths are dominant (A_), so could be AA or Aa
  • Light moths are recessive (aa), so must be aa

Suppose:

  • 50 are AA
  • 70 are Aa
  • 80 are aa

Genotype frequencies:

  • AA: 50200=0.25\frac{50}{200} = 0.2520050​=0.25
  • Aa: 70200=0.35\frac{70}{200} = 0.3520070​=0.35
  • aa: 80200=0.40\frac{80}{200} = 0.4020080​=0.40

Number of moths:

  • AA = 50
  • Aa = 70
  • aa = 80

3. Allele Frequencies

Each moth has 2 alleles:

  • Total alleles = 200×2=400200 \times 2 = 400200×2=400

Count A alleles:

  • AA = 50 × 2 = 100 A alleles
  • Aa = 70 × 1 = 70 A alleles
    → Total A = 170

Count a alleles:

  • aa = 80 × 2 = 160 a alleles
  • Aa = 70 × 1 = 70 a alleles
    → Total a = 230

Allele frequencies:

  • A = 170400=0.425\frac{170}{400} = 0.425400170​=0.425
  • a = 230400=0.575\frac{230}{400} = 0.575400230​=0.575

Conclusion:

In generation 5:

  • Phenotype frequencies: 60% dark, 40% light
  • Genotype frequencies: 25% AA, 35% Aa, 40% aa
  • Allele frequencies: A = 42.5%, a = 57.5%

These frequencies show how natural selection or genetic drift may affect populations across generations

.

By admin

Leave a Reply

Your email address will not be published. Required fields are marked *