Write a program using integers user_num and x as input, and output user_num divided by x three times.

Write a program using integers user_num and x as input, and output user_num divided by x three times. Ex: If the input is: 2000 2 Then the output is: 1000 500 250 Note: In Python 3, integer division discards fractions. Ex: 6 // 4 is 1 (the 0.5 is discarded). 333296:2048946.qx3zqy7 LAB ACTIVITY 2.12.1: LAB: Divide by x 1 Type your code here. main.py 0/10 Load default template…

The Correct Answer and Explanation is:

✅ Correct Python Code:

pythonCopyEdit# Take two integer inputs from the user
user_num = int(input())
x = int(input())

# Perform integer division three times and print the result each time
user_num = user_num // x
print(user_num, end=' ')

user_num = user_num // x
print(user_num, end=' ')

user_num = user_num // x
print(user_num)

💡 Explanation

This program asks the user for two integers: user_num and x. It then divides user_num by x three times in a row, using integer division, and prints the result after each division.

In Python, the operator // is used for integer division. This means it divides the number and discards the remainder or any decimal part. For example, 7 // 2 gives 3 instead of 3.5.

Let us go step by step using the example input:

yamlCopyEditInput:
2000
2

1. First, user_num = 2000, x = 2
2. First division: 2000 // 2 = 1000 → print 1000
3. Second division: 1000 // 2 = 500 → print 500
4. Third division: 500 // 2 = 250 → print 250

So the output is:

yamlCopyEdit1000 500 250

Notice that user_num is updated each time with the result of the previous division. This way, we keep dividing the current value of user_num by x again.

We use print(..., end=' ') for the first two print statements so that the outputs appear on the same line separated by spaces. The final print(user_num) ends with a newline by default, which matches the expected output format.

This logic works correctly as long as the user inputs integers and x is not zero. If x were zero, the program would crash due to a division by zero error, but the question assumes valid input is provided.