what is the mass in grams of 34.5 mol of copper (1) sulfate
The correct answer and explanation is:
To find the mass in grams of 34.5 mol of copper(I) sulfate (Cu₂SO₄), we use the formula: Mass=Moles×Molar Mass\text{Mass} = \text{Moles} \times \text{Molar Mass}
Step 1: Determine the Molar Mass of Copper(I) Sulfate (Cu₂SO₄)
- Cu (Copper): 63.55 g/mol
- S (Sulfur): 32.07 g/mol
- O₄ (Oxygen): 16.00 × 4 = 64.00 g/mol
Molar Mass of Cu₂SO₄=(63.55×2)+32.07+64.00=127.10+32.07+64.00=223.17 g/mol\text{Molar Mass of Cu₂SO₄} = (63.55 \times 2) + 32.07 + 64.00 = 127.10 + 32.07 + 64.00 = 223.17 \text{ g/mol}
Step 2: Multiply by the Number of Moles
Mass=34.5 mol×223.17 g/mol=7709.37 grams\text{Mass} = 34.5 \text{ mol} \times 223.17 \text{ g/mol} = 7709.37 \text{ grams}
✅ Final Answer:
7709.37 grams\boxed{7709.37 \text{ grams}}
💡 Explanation (300 words):
To calculate the mass of a substance from the number of moles, you multiply the number of moles by the molar mass of the substance. This is because one mole of any substance contains Avogadro’s number of particles (6.022 × 10²³) and weighs exactly its molar mass in grams.
In this question, the substance is copper(I) sulfate, which has the chemical formula Cu₂SO₄. This formula indicates that each formula unit contains 2 atoms of copper (Cu), 1 atom of sulfur (S), and 4 atoms of oxygen (O).
Using the periodic table:
- Copper has a molar mass of about 63.55 g/mol.
- Sulfur is 32.07 g/mol.
- Oxygen is 16.00 g/mol.
Adding them up: (2×63.55)+32.07+(4×16.00)=223.17 g/mol(2 \times 63.55) + 32.07 + (4 \times 16.00) = 223.17 \text{ g/mol}
This means that 1 mole of Cu₂SO₄ weighs 223.17 grams.
Now, you are given 34.5 moles of Cu₂SO₄. Multiply: 34.5 mol×223.17 g/mol=7709.37 grams34.5 \text{ mol} \times 223.17 \text{ g/mol} = 7709.37 \text{ grams}
So, the mass of 34.5 moles of copper(I) sulfate is 7709.37 grams. This is a direct application of the molar relationship between amount and mass in chemistry.