What is the Chemical symbol of Sodium bromide?
The correct answer and explanation is :
The chemical symbol of Sodium bromide is NaBr.
Explanation:
Sodium bromide is an ionic compound formed by the combination of sodium (Na) and bromine (Br). It consists of one sodium (Na) ion and one bromide (Br) ion, held together by an ionic bond.
- Sodium (Na):
- Sodium is an alkali metal located in Group 1 of the periodic table. Its atomic number is 11. Sodium atoms have one electron in their outermost shell, which they tend to lose in order to achieve a stable electron configuration similar to that of noble gases. By losing this electron, sodium becomes a positively charged ion (Na⁺).
- Bromine (Br):
- Bromine is a halogen, located in Group 17 of the periodic table, with an atomic number of 35. Bromine atoms have seven electrons in their outermost shell and need one additional electron to complete their valence shell. As a result, bromine tends to gain an electron to form a negatively charged ion (Br⁻).
- Formation of Sodium Bromide (NaBr):
- When sodium (Na) reacts with bromine (Br), sodium loses its single outer electron, becoming a Na⁺ ion. Bromine, on the other hand, gains this electron, forming a Br⁻ ion. The oppositely charged ions (Na⁺ and Br⁻) are attracted to each other due to electrostatic forces, forming an ionic bond and producing sodium bromide (NaBr).
- Properties of Sodium Bromide:
- Sodium bromide is a white, crystalline solid at room temperature. It is highly soluble in water. The ionic nature of NaBr gives it high melting and boiling points compared to covalent compounds. Sodium bromide is commonly used in photography, medicine, and in the manufacture of other chemicals like bromine compounds.
In summary, NaBr is formed through the ionic bonding between sodium (Na) and bromine (Br), creating a stable compound commonly used in various industrial and chemical applications.